13143130113 has 4 divisors (see below), whose sum is σ = 17524173488. Its totient is φ = 8762086740.

The previous prime is 13143130093. The next prime is 13143130183. The reversal of 13143130113 is 31103134131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13143130113 - 2⁵ = 13143130081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13143130113.

It is not an unprimeable number, because it can be changed into a prime (13143130183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190521683 + ... + 2190521688.

It is an arithmetic number, because the mean of its divisors is an integer number (4381043372).

Almost surely, 2^13143130113 is an apocalyptic number.

It is an amenable number.

13143130113 is a deficient number, since it is larger than the sum of its proper divisors (4381043375).

13143130113 is an equidigital number, since it uses as much as digits as its factorization.

13143130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4381043374.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 13143130113 its reverse (31103134131), we get a palindrome (44246264244).

The spelling of 13143130113 in words is "thirteen billion, one hundred forty-three million, one hundred thirty thousand, one hundred thirteen".