131433011101142 has 4 divisors (see below), whose sum is σ = 197149516651716. Its totient is φ = 65716505550570.

The previous prime is 131433011101129. The next prime is 131433011101193. The reversal of 131433011101142 is 241101110334131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131433011101142² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32858252775284 + ... + 32858252775287.

It is an arithmetic number, because the mean of its divisors is an integer number (49287379162929).

Almost surely, 2^{131433011101142} is an apocalyptic number.

131433011101142 is a deficient number, since it is larger than the sum of its proper divisors (65716505550574).

131433011101142 is an equidigital number, since it uses as much as digits as its factorization.

131433011101142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65716505550573.

The product of its (nonzero) digits is 864, while the sum is 26.

Adding to 131433011101142 its reverse (241101110334131), we get a palindrome (372534121435273).

The spelling of 131433011101142 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, eleven million, one hundred one thousand, one hundred forty-two".