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131433332543 = 997131828819
BaseRepresentation
bin111101001101000001…
…0010111111100111111
3110120020211000002020022
41322122002113330333
54123133413120133
6140214000242355
712332016615302
oct1723202277477
9416224002208
10131433332543
1150816765087
12215809103bb
13c517b240b6
14650b9b6b39
153643ade998
hex1e9a097f3f

131433332543 has 4 divisors (see below), whose sum is σ = 131565162360. Its totient is φ = 131301502728.

The previous prime is 131433332519. The next prime is 131433332557. The reversal of 131433332543 is 345233334131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131433332543 - 226 = 131366223679 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131433232543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65913413 + ... + 65915406.

It is an arithmetic number, because the mean of its divisors is an integer number (32891290590).

Almost surely, 2131433332543 is an apocalyptic number.

131433332543 is a deficient number, since it is larger than the sum of its proper divisors (131829817).

131433332543 is an equidigital number, since it uses as much as digits as its factorization.

131433332543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131829816.

The product of its digits is 116640, while the sum is 35.

Adding to 131433332543 its reverse (345233334131), we get a palindrome (476666666674).

The spelling of 131433332543 in words is "one hundred thirty-one billion, four hundred thirty-three million, three hundred thirty-two thousand, five hundred forty-three".

Divisors: 1 997 131828819 131433332543