Base | Representation |
---|---|
bin | 1011111101000011000000… |
… | …0011101001000110111111 |
3 | 1201112111102120112122002122 |
4 | 2333100300003221012333 |
5 | 3210320143440440233 |
6 | 43541555240513155 |
7 | 2524402600154024 |
oct | 277206003510677 |
9 | 51474376478078 |
10 | 13143406186943 |
11 | 42080a616556a |
12 | 158334417b7bb |
13 | 74455812b336 |
14 | 336203b9154b |
15 | 17bd54433d98 |
hex | bf4300e91bf |
13143406186943 has 2 divisors, whose sum is σ = 13143406186944. Its totient is φ = 13143406186942.
The previous prime is 13143406186819. The next prime is 13143406186979. The reversal of 13143406186943 is 34968160434131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13143406186943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143406116943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571703093471 + 6571703093472.
It is an arithmetic number, because the mean of its divisors is an integer number (6571703093472).
Almost surely, 213143406186943 is an apocalyptic number.
13143406186943 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143406186943 is an equidigital number, since it uses as much as digits as its factorization.
13143406186943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4478976, while the sum is 53.
The spelling of 13143406186943 in words is "thirteen trillion, one hundred forty-three billion, four hundred six million, one hundred eighty-six thousand, nine hundred forty-three".
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