Base | Representation |
---|---|
bin | 111101001101001110… |
… | …1010111001000111111 |
3 | 110120021022022111201001 |
4 | 1322122131113020333 |
5 | 4123142221011403 |
6 | 140214412031131 |
7 | 12332134011655 |
oct | 1723235271077 |
9 | 416238274631 |
10 | 131440407103 |
11 | 5081a757325 |
12 | 215831624a7 |
13 | c519430225 |
14 | 650c8d8dd5 |
15 | 364453ac1d |
hex | 1e9a75723f |
131440407103 has 2 divisors, whose sum is σ = 131440407104. Its totient is φ = 131440407102.
The previous prime is 131440407089. The next prime is 131440407187. The reversal of 131440407103 is 301704044131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131440407103 - 213 = 131440398911 is a prime.
It is a super-3 number, since 3×1314404071033 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131440407193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720203551 + 65720203552.
It is an arithmetic number, because the mean of its divisors is an integer number (65720203552).
Almost surely, 2131440407103 is an apocalyptic number.
131440407103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131440407103 is an equidigital number, since it uses as much as digits as its factorization.
131440407103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
The spelling of 131440407103 in words is "one hundred thirty-one billion, four hundred forty million, four hundred seven thousand, one hundred three".
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