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131440436527 is a prime number
BaseRepresentation
bin111101001101001110…
…1011110010100101111
3110120021022101000001211
41322122131132110233
54123142222432102
6140214412415251
712332134163521
oct1723235362457
9416238330054
10131440436527
115081a777444
1221583177527
13c51944073a
14650c905a11
1536445447d7
hex1e9a75e52f

131440436527 has 2 divisors, whose sum is σ = 131440436528. Its totient is φ = 131440436526.

The previous prime is 131440436441. The next prime is 131440436557. The reversal of 131440436527 is 725634044131.

It is a strong prime.

It is an emirp because it is prime and its reverse (725634044131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131440436527 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131440436527.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131440436557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720218263 + 65720218264.

It is an arithmetic number, because the mean of its divisors is an integer number (65720218264).

Almost surely, 2131440436527 is an apocalyptic number.

131440436527 is a deficient number, since it is larger than the sum of its proper divisors (1).

131440436527 is an equidigital number, since it uses as much as digits as its factorization.

131440436527 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 40.

The spelling of 131440436527 in words is "one hundred thirty-one billion, four hundred forty million, four hundred thirty-six thousand, five hundred twenty-seven".