Base | Representation |
---|---|
bin | 11000011110111001… |
… | …10100111111011101 |
3 | 1020221000222100010001 |
4 | 30033130310333131 |
5 | 203404343222323 |
6 | 10012140014301 |
7 | 643503103303 |
oct | 141734647735 |
9 | 36830870101 |
10 | 13144117213 |
11 | 5635569897 |
12 | 2669b31391 |
13 | 13161c1066 |
14 | 8c9962273 |
15 | 51de1d3ad |
hex | 30f734fdd |
13144117213 has 2 divisors, whose sum is σ = 13144117214. Its totient is φ = 13144117212.
The previous prime is 13144117199. The next prime is 13144117229. The reversal of 13144117213 is 31271144131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11451782169 + 1692335044 = 107013^2 + 41138^2 .
It is a cyclic number.
It is not a de Polignac number, because 13144117213 - 233 = 4554182621 is a prime.
It is a super-3 number, since 3×131441172133 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13144115213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572058606 + 6572058607.
It is an arithmetic number, because the mean of its divisors is an integer number (6572058607).
Almost surely, 213144117213 is an apocalyptic number.
It is an amenable number.
13144117213 is a deficient number, since it is larger than the sum of its proper divisors (1).
13144117213 is an equidigital number, since it uses as much as digits as its factorization.
13144117213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2016, while the sum is 28.
The spelling of 13144117213 in words is "thirteen billion, one hundred forty-four million, one hundred seventeen thousand, two hundred thirteen".
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