Base | Representation |
---|---|
bin | 111101001101010000… |
… | …0010010011100101010 |
3 | 110120021100202111010021 |
4 | 1322122200102130222 |
5 | 4123142420034224 |
6 | 140214440311054 |
7 | 12332143355512 |
oct | 1723240223452 |
9 | 416240674107 |
10 | 131441174314 |
11 | 5082013078a |
12 | 2158347248a |
13 | c51963b4b8 |
14 | 650ca58842 |
15 | 364463d1e4 |
hex | 1e9a81272a |
131441174314 has 4 divisors (see below), whose sum is σ = 197161761474. Its totient is φ = 65720587156.
The previous prime is 131441174299. The next prime is 131441174353. The reversal of 131441174314 is 413471144131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 413471144131 = 90617 ⋅4562843.
It can be written as a sum of positive squares in only one way, i.e., 85127982289 + 46313192025 = 291767^2 + 215205^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 131441174314.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32860293577 + ... + 32860293580.
Almost surely, 2131441174314 is an apocalyptic number.
131441174314 is a deficient number, since it is larger than the sum of its proper divisors (65720587160).
131441174314 is an equidigital number, since it uses as much as digits as its factorization.
131441174314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65720587159.
The product of its digits is 16128, while the sum is 34.
The spelling of 131441174314 in words is "one hundred thirty-one billion, four hundred forty-one million, one hundred seventy-four thousand, three hundred fourteen".
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