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131442213334253 = 472796642836899
BaseRepresentation
bin11101111000101111000110…
…011011110010110011101101
3122020101202022211211122112212
4131320233012123302303231
5114212022123103144003
61143315415202540205
736454246402606043
oct3570570633626355
9566352284748485
10131442213334253
1138977369810318
12128aa46b367665
135845c41961343
142465ba0cc4393
15102e1a8692dd8
hex778bc66f2ced

131442213334253 has 4 divisors (see below), whose sum is σ = 134238856171200. Its totient is φ = 128645570497308.

The previous prime is 131442213334213. The next prime is 131442213334273. The reversal of 131442213334253 is 352433312244131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131442213334253 - 28 = 131442213333997 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131442213334253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131442213334213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1398321418403 + ... + 1398321418496.

It is an arithmetic number, because the mean of its divisors is an integer number (33559714042800).

Almost surely, 2131442213334253 is an apocalyptic number.

It is an amenable number.

131442213334253 is a deficient number, since it is larger than the sum of its proper divisors (2796642836947).

131442213334253 is an equidigital number, since it uses as much as digits as its factorization.

131442213334253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2796642836946.

The product of its digits is 622080, while the sum is 41.

Adding to 131442213334253 its reverse (352433312244131), we get a palindrome (483875525578384).

The spelling of 131442213334253 in words is "one hundred thirty-one trillion, four hundred forty-two billion, two hundred thirteen million, three hundred thirty-four thousand, two hundred fifty-three".

Divisors: 1 47 2796642836899 131442213334253