131443104614111 has 2 divisors, whose sum is σ = 131443104614112. Its totient is φ = 131443104614110.

The previous prime is 131443104614099. The next prime is 131443104614113. The reversal of 131443104614111 is 111416401344131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131443104614111 - 2⁶ = 131443104614047 is a prime.

It is a super-2 number, since 2×131443104614111² (a number of 29 digits) contains 22 as substring.

Together with 131443104614113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131443104614113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65721552307055 + 65721552307056.

It is an arithmetic number, because the mean of its divisors is an integer number (65721552307056).

Almost surely, 2^{131443104614111} is an apocalyptic number.

131443104614111 is a deficient number, since it is larger than the sum of its proper divisors (1).

131443104614111 is an equidigital number, since it uses as much as digits as its factorization.

131443104614111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

Adding to 131443104614111 its reverse (111416401344131), we get a palindrome (242859505958242).

The spelling of 131443104614111 in words is "one hundred thirty-one trillion, four hundred forty-three billion, one hundred four million, six hundred fourteen thousand, one hundred eleven".