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131444230991 is a prime number
BaseRepresentation
bin111101001101010101…
…1111100101101001111
3110120021120111210002112
41322122223330231033
54123144210342431
6140215030014235
712332211346223
oct1723253745517
9416246453075
10131444230991
1150821929267
12215844a737b
13c51a16b898
14650d212783
153644a43c2b
hex1e9aafcb4f

131444230991 has 2 divisors, whose sum is σ = 131444230992. Its totient is φ = 131444230990.

The previous prime is 131444230969. The next prime is 131444230993. The reversal of 131444230991 is 199032444131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131444230991 - 26 = 131444230927 is a prime.

Together with 131444230993, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131444230993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65722115495 + 65722115496.

It is an arithmetic number, because the mean of its divisors is an integer number (65722115496).

Almost surely, 2131444230991 is an apocalyptic number.

131444230991 is a deficient number, since it is larger than the sum of its proper divisors (1).

131444230991 is an equidigital number, since it uses as much as digits as its factorization.

131444230991 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 131444230991 in words is "one hundred thirty-one billion, four hundred forty-four million, two hundred thirty thousand, nine hundred ninety-one".