13144441 has 4 divisors (see below), whose sum is σ = 13152384. Its totient is φ = 13136500.

The previous prime is 13144423. The next prime is 13144459. The reversal of 13144441 is 14444131.

13144441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14444131 = 13 ⋅1111087.

It is an interprime number because it is at equal distance from previous prime (13144423) and next prime (13144459).

It is a cyclic number.

It is not a de Polignac number, because 13144441 - 2¹⁷ = 13013369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13144141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 445 + ... + 5146.

It is an arithmetic number, because the mean of its divisors is an integer number (3288096).

Almost surely, 2^13144441 is an apocalyptic number.

It is an amenable number.

13144441 is a deficient number, since it is larger than the sum of its proper divisors (7943).

13144441 is an equidigital number, since it uses as much as digits as its factorization.

13144441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7942.

The product of its digits is 768, while the sum is 22.

The square root of 13144441 is about 3625.5263066209. The cubic root of 13144441 is about 236.0011071958.

Adding to 13144441 its reverse (14444131), we get a palindrome (27588572).

The spelling of 13144441 in words is "thirteen million, one hundred forty-four thousand, four hundred forty-one".