13144443113 has 2 divisors, whose sum is σ = 13144443114. Its totient is φ = 13144443112.

The previous prime is 13144443107. The next prime is 13144443119. The reversal of 13144443113 is 31134444131.

13144443113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13144443107) and next prime (13144443119).

It can be written as a sum of positive squares in only one way, i.e., 10743737104 + 2400706009 = 103652^2 + 48997^2 .

It is a cyclic number.

It is not a de Polignac number, because 13144443113 - 2¹² = 13144439017 is a prime.

It is not a weakly prime, because it can be changed into another prime (13144443119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572221556 + 6572221557.

It is an arithmetic number, because the mean of its divisors is an integer number (6572221557).

Almost surely, 2^13144443113 is an apocalyptic number.

It is an amenable number.

13144443113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13144443113 is an equidigital number, since it uses as much as digits as its factorization.

13144443113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 29.

Adding to 13144443113 its reverse (31134444131), we get a palindrome (44278887244).

The spelling of 13144443113 in words is "thirteen billion, one hundred forty-four million, four hundred forty-three thousand, one hundred thirteen".