Base | Representation |
---|---|
bin | 10011001000001110111… |
… | …100001001010110100000 |
3 | 11122122222111200100221102 |
4 | 103020032330021112200 |
5 | 133014104210444134 |
6 | 2443513341013532 |
7 | 163653541042013 |
oct | 23101674112640 |
9 | 4578874610842 |
10 | 1314510640544 |
11 | 467531a95202 |
12 | 192916b542a8 |
13 | 96c5b44568a |
14 | 478a07c737a |
15 | 242d7cc437e |
hex | 1320ef095a0 |
1314510640544 has 12 divisors (see below), whose sum is σ = 2587942823634. Its totient is φ = 657255320256.
The previous prime is 1314510640529. The next prime is 1314510640589. The reversal of 1314510640544 is 4450460154131.
It can be written as a sum of positive squares in only one way, i.e., 1201084483600 + 113426156944 = 1095940^2 + 336788^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1314510640498 and 1314510640507.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20539228727 + ... + 20539228790.
Almost surely, 21314510640544 is an apocalyptic number.
It is an amenable number.
1314510640544 is a deficient number, since it is larger than the sum of its proper divisors (1273432183090).
1314510640544 is an equidigital number, since it uses as much as digits as its factorization.
1314510640544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41078457527 (or 41078457519 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 1314510640544 its reverse (4450460154131), we get a palindrome (5764970794675).
The spelling of 1314510640544 in words is "one trillion, three hundred fourteen billion, five hundred ten million, six hundred forty thousand, five hundred forty-four".
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