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1314510640544 = 2541078457517
BaseRepresentation
bin10011001000001110111…
…100001001010110100000
311122122222111200100221102
4103020032330021112200
5133014104210444134
62443513341013532
7163653541042013
oct23101674112640
94578874610842
101314510640544
11467531a95202
12192916b542a8
1396c5b44568a
14478a07c737a
15242d7cc437e
hex1320ef095a0

1314510640544 has 12 divisors (see below), whose sum is σ = 2587942823634. Its totient is φ = 657255320256.

The previous prime is 1314510640529. The next prime is 1314510640589. The reversal of 1314510640544 is 4450460154131.

It can be written as a sum of positive squares in only one way, i.e., 1201084483600 + 113426156944 = 1095940^2 + 336788^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1314510640498 and 1314510640507.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20539228727 + ... + 20539228790.

Almost surely, 21314510640544 is an apocalyptic number.

It is an amenable number.

1314510640544 is a deficient number, since it is larger than the sum of its proper divisors (1273432183090).

1314510640544 is an equidigital number, since it uses as much as digits as its factorization.

1314510640544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41078457527 (or 41078457519 counting only the distinct ones).

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 1314510640544 its reverse (4450460154131), we get a palindrome (5764970794675).

The spelling of 1314510640544 in words is "one trillion, three hundred fourteen billion, five hundred ten million, six hundred forty thousand, five hundred forty-four".

Divisors: 1 2 4 8 16 32 41078457517 82156915034 164313830068 328627660136 657255320272 1314510640544