Base | Representation |
---|---|
bin | 111101001101100011… |
… | …0101000000001011001 |
3 | 110120022001200001220112 |
4 | 1322123012220001121 |
5 | 4123203003133103 |
6 | 140215435534105 |
7 | 12332324653364 |
oct | 1723306500131 |
9 | 416261601815 |
10 | 131451224153 |
11 | 50825875337 |
12 | 215868ba335 |
13 | c51b749952 |
14 | 65101130db |
15 | 3645475cd8 |
hex | 1e9b1a8059 |
131451224153 has 2 divisors, whose sum is σ = 131451224154. Its totient is φ = 131451224152.
The previous prime is 131451224141. The next prime is 131451224207. The reversal of 131451224153 is 351422154131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80308758544 + 51142465609 = 283388^2 + 226147^2 .
It is a cyclic number.
It is not a de Polignac number, because 131451224153 - 26 = 131451224089 is a prime.
It is not a weakly prime, because it can be changed into another prime (131451224453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65725612076 + 65725612077.
It is an arithmetic number, because the mean of its divisors is an integer number (65725612077).
Almost surely, 2131451224153 is an apocalyptic number.
It is an amenable number.
131451224153 is a deficient number, since it is larger than the sum of its proper divisors (1).
131451224153 is an equidigital number, since it uses as much as digits as its factorization.
131451224153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 32.
Adding to 131451224153 its reverse (351422154131), we get a palindrome (482873378284).
The spelling of 131451224153 in words is "one hundred thirty-one billion, four hundred fifty-one million, two hundred twenty-four thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.123 sec. • engine limits •