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131451224453 is a prime number
BaseRepresentation
bin111101001101100011…
…0101000000110000101
3110120022001200002022122
41322123012220012011
54123203003140303
6140215435535325
712332324654303
oct1723306500605
9416261602278
10131451224453
115082587558a
12215868ba545
13c51b749b23
146510113273
153645475e38
hex1e9b1a8185

131451224453 has 2 divisors, whose sum is σ = 131451224454. Its totient is φ = 131451224452.

The previous prime is 131451224383. The next prime is 131451224497. The reversal of 131451224453 is 354422154131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76150058209 + 55301166244 = 275953^2 + 235162^2 .

It is a cyclic number.

It is not a de Polignac number, because 131451224453 - 220 = 131450175877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131451224153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65725612226 + 65725612227.

It is an arithmetic number, because the mean of its divisors is an integer number (65725612227).

Almost surely, 2131451224453 is an apocalyptic number.

It is an amenable number.

131451224453 is a deficient number, since it is larger than the sum of its proper divisors (1).

131451224453 is an equidigital number, since it uses as much as digits as its factorization.

131451224453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 57600, while the sum is 35.

Adding to 131451224453 its reverse (354422154131), we get a palindrome (485873378584).

The spelling of 131451224453 in words is "one hundred thirty-one billion, four hundred fifty-one million, two hundred twenty-four thousand, four hundred fifty-three".