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13149766423957 is a prime number
BaseRepresentation
bin1011111101011010101100…
…1010000001010110010101
31201120002211211110011001111
42333112223022001112111
53210421210201031312
643544530322455021
72525016320244052
oct277265312012625
951502754404044
1013149766423957
11420a86a372799
12158461a204471
1374502ca259a7
14336648774029
1517c0c79c88a7
hexbf5ab281595

13149766423957 has 2 divisors, whose sum is σ = 13149766423958. Its totient is φ = 13149766423956.

The previous prime is 13149766423921. The next prime is 13149766423967. The reversal of 13149766423957 is 75932466794131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8447573673841 + 4702192750116 = 2906471^2 + 2168454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13149766423957 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13149766423892 and 13149766423901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13149766423967) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6574883211978 + 6574883211979.

It is an arithmetic number, because the mean of its divisors is an integer number (6574883211979).

Almost surely, 213149766423957 is an apocalyptic number.

It is an amenable number.

13149766423957 is a deficient number, since it is larger than the sum of its proper divisors (1).

13149766423957 is an equidigital number, since it uses as much as digits as its factorization.

13149766423957 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 205752960, while the sum is 67.

The spelling of 13149766423957 in words is "thirteen trillion, one hundred forty-nine billion, seven hundred sixty-six million, four hundred twenty-three thousand, nine hundred fifty-seven".