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13150022117 is a prime number
BaseRepresentation
bin11000011111100110…
…10110100111100101
31020221110002100010012
430033303112213211
5203412401201432
610012510340005
7643604225621
oct141763264745
936843070105
1013150022117
115638932281
12266baba605
1313174aa99b
148ca65c181
1551e6d7cb2
hex30fcd69e5

13150022117 has 2 divisors, whose sum is σ = 13150022118. Its totient is φ = 13150022116.

The previous prime is 13150022071. The next prime is 13150022143. The reversal of 13150022117 is 71122005131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12988249156 + 161772961 = 113966^2 + 12719^2 .

It is an emirp because it is prime and its reverse (71122005131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13150022117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13150022092 and 13150022101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13150022917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6575011058 + 6575011059.

It is an arithmetic number, because the mean of its divisors is an integer number (6575011059).

Almost surely, 213150022117 is an apocalyptic number.

It is an amenable number.

13150022117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13150022117 is an equidigital number, since it uses as much as digits as its factorization.

13150022117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 23.

Adding to 13150022117 its reverse (71122005131), we get a palindrome (84272027248).

The spelling of 13150022117 in words is "thirteen billion, one hundred fifty million, twenty-two thousand, one hundred seventeen".