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131502563740 = 2256575128187
BaseRepresentation
bin111101001111000101…
…0011110000110011100
3110120102122021101120201
41322132022132012130
54123304124014430
6140224512153244
712333520230442
oct1723612360634
9416378241521
10131502563740
1150851850549
122159bb38824
13c5292839c2
146516c78b92
153649c178ca
hex1e9e29e19c

131502563740 has 12 divisors (see below), whose sum is σ = 276155383896. Its totient is φ = 52601025488.

The previous prime is 131502563737. The next prime is 131502563789. The reversal of 131502563740 is 47365205131.

It is a self number, because there is not a number n which added to its sum of digits gives 131502563740.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3287564074 + ... + 3287564113.

It is an arithmetic number, because the mean of its divisors is an integer number (23012948658).

Almost surely, 2131502563740 is an apocalyptic number.

131502563740 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131502563740 is an abundant number, since it is smaller than the sum of its proper divisors (144652820156).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131502563740 is a wasteful number, since it uses less digits than its factorization.

131502563740 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6575128196 (or 6575128194 counting only the distinct ones).

The product of its (nonzero) digits is 75600, while the sum is 37.

Adding to 131502563740 its reverse (47365205131), we get a palindrome (178867768871).

The spelling of 131502563740 in words is "one hundred thirty-one billion, five hundred two million, five hundred sixty-three thousand, seven hundred forty".

Divisors: 1 2 4 5 10 20 6575128187 13150256374 26300512748 32875640935 65751281870 131502563740