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131503994981 is a prime number
BaseRepresentation
bin111101001111000111…
…1111011100001100101
3110120102201222002212122
41322132033323201211
54123310010314411
6140225002555325
712333535341242
oct1723617734145
9416381862778
10131503994981
1150852638897
12215a0508b45
13c5296652a8
14651712c5c9
153649deb9db
hex1e9e3fb865

131503994981 has 2 divisors, whose sum is σ = 131503994982. Its totient is φ = 131503994980.

The previous prime is 131503994971. The next prime is 131503995001. The reversal of 131503994981 is 189499305131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118452988900 + 13051006081 = 344170^2 + 114241^2 .

It is a cyclic number.

It is not a de Polignac number, because 131503994981 - 214 = 131503978597 is a prime.

It is a super-2 number, since 2×1315039949812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131503994911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65751997490 + 65751997491.

It is an arithmetic number, because the mean of its divisors is an integer number (65751997491).

Almost surely, 2131503994981 is an apocalyptic number.

It is an amenable number.

131503994981 is a deficient number, since it is larger than the sum of its proper divisors (1).

131503994981 is an equidigital number, since it uses as much as digits as its factorization.

131503994981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1049760, while the sum is 53.

The spelling of 131503994981 in words is "one hundred thirty-one billion, five hundred three million, nine hundred ninety-four thousand, nine hundred eighty-one".