Base | Representation |
---|---|
bin | 111101001111010111… |
… | …1110111001010000111 |
3 | 110120110022201101100101 |
4 | 1322132233313022013 |
5 | 4123314131200303 |
6 | 140225502224531 |
7 | 12333666443545 |
oct | 1723657671207 |
9 | 416408641311 |
10 | 131512365703 |
11 | 50857335944 |
12 | 215a3285147 |
13 | c52b306394 |
14 | 65182aad95 |
15 | 364aa01d1d |
hex | 1e9ebf7287 |
131512365703 has 2 divisors, whose sum is σ = 131512365704. Its totient is φ = 131512365702.
The previous prime is 131512365701. The next prime is 131512365713. The reversal of 131512365703 is 307563215131.
It is a weak prime.
It is an emirp because it is prime and its reverse (307563215131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131512365703 - 21 = 131512365701 is a prime.
It is a super-2 number, since 2×1315123657032 (a number of 23 digits) contains 22 as substring.
Together with 131512365701, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131512365701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65756182851 + 65756182852.
It is an arithmetic number, because the mean of its divisors is an integer number (65756182852).
Almost surely, 2131512365703 is an apocalyptic number.
131512365703 is a deficient number, since it is larger than the sum of its proper divisors (1).
131512365703 is an equidigital number, since it uses as much as digits as its factorization.
131512365703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56700, while the sum is 37.
The spelling of 131512365703 in words is "one hundred thirty-one billion, five hundred twelve million, three hundred sixty-five thousand, seven hundred three".
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