Base | Representation |
---|---|
bin | 111101001111101110… |
… | …1001101001001011101 |
3 | 110120111011002021121222 |
4 | 1322133131031021131 |
5 | 4123330202033003 |
6 | 140231005103125 |
7 | 12334202461322 |
oct | 1723735151135 |
9 | 416434067558 |
10 | 131524252253 |
11 | 50863014439 |
12 | 215a7257aa5 |
13 | c530908844 |
14 | 6519ac2b49 |
15 | 364ba9dc38 |
hex | 1e9f74d25d |
131524252253 has 2 divisors, whose sum is σ = 131524252254. Its totient is φ = 131524252252.
The previous prime is 131524252213. The next prime is 131524252289. The reversal of 131524252253 is 352252425131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102229191289 + 29295060964 = 319733^2 + 171158^2 .
It is a cyclic number.
It is not a de Polignac number, because 131524252253 - 212 = 131524248157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131524252213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65762126126 + 65762126127.
It is an arithmetic number, because the mean of its divisors is an integer number (65762126127).
Almost surely, 2131524252253 is an apocalyptic number.
It is an amenable number.
131524252253 is a deficient number, since it is larger than the sum of its proper divisors (1).
131524252253 is an equidigital number, since it uses as much as digits as its factorization.
131524252253 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72000, while the sum is 35.
Adding to 131524252253 its reverse (352252425131), we get a palindrome (483776677384).
The spelling of 131524252253 in words is "one hundred thirty-one billion, five hundred twenty-four million, two hundred fifty-two thousand, two hundred fifty-three".
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