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131533301212000 = 25537322911511709
BaseRepresentation
bin11101111010000011111011…
…101100011110001101100000
3122020201110102220202021101121
4131322003323230132031200
5114220020200102241000
61143425321524142024
736463652552026612
oct3572037354361540
9566643386667347
10131533301212000
1138a01a61517026
1212904050537914
1358516c9c7b75c
14246a362486db2
15103173a2adb1a
hex77a0fbb1e360

131533301212000 has 384 divisors, whose sum is σ = 329513561395200. Its totient is φ = 51590891520000.

The previous prime is 131533301211971. The next prime is 131533301212009. The reversal of 131533301212000 is 212103335131.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131533301212009) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 76965067146 + ... + 76965068854.

It is an arithmetic number, because the mean of its divisors is an integer number (858108232800).

Almost surely, 2131533301212000 is an apocalyptic number.

131533301212000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131533301212000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164756780697600).

131533301212000 is an abundant number, since it is smaller than the sum of its proper divisors (197980260183200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131533301212000 is a wasteful number, since it uses less digits than its factorization.

131533301212000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3187 (or 3169 counting only the distinct ones).

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 131533301212000 its reverse (212103335131), we get a palindrome (131745404547131).

The spelling of 131533301212000 in words is "one hundred thirty-one trillion, five hundred thirty-three billion, three hundred one million, two hundred twelve thousand".