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131533401412111 = 236193751533437
BaseRepresentation
bin11101111010000100000001…
…101010101101001000001111
3122020201110200220021222002211
4131322010001222231020033
5114220020401230141421
61143425335503531251
736463655206514326
oct3572040152551017
9566643626258084
10131533401412111
1138a02003034936
1212904079bb9b27
13585171496236a
14246a3718cb0bd
151031743ea29e1
hex77a101aad20f

131533401412111 has 8 divisors (see below), whose sum is σ = 139502281755744. Its totient is φ = 123752024135520.

The previous prime is 131533401412069. The next prime is 131533401412123. The reversal of 131533401412111 is 111214104335131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131533401412111 - 27 = 131533401411983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131533401412411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46875765316 + ... + 46875768121.

It is an arithmetic number, because the mean of its divisors is an integer number (17437785219468).

Almost surely, 2131533401412111 is an apocalyptic number.

131533401412111 is a deficient number, since it is larger than the sum of its proper divisors (7968880343633).

131533401412111 is an equidigital number, since it uses as much as digits as its factorization.

131533401412111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93751533521.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 131533401412111 its reverse (111214104335131), we get a palindrome (242747505747242).

The spelling of 131533401412111 in words is "one hundred thirty-one trillion, five hundred thirty-three billion, four hundred one million, four hundred twelve thousand, one hundred eleven".

Divisors: 1 23 61 1403 93751533437 2156285269051 5718843539657 131533401412111