Base | Representation |
---|---|
bin | 10011001001000000000… |
… | …001001110001010010111 |
3 | 11122202002220002010121111 |
4 | 103021000001032022113 |
5 | 133022301004221201 |
6 | 2444131153355451 |
7 | 164013126663646 |
oct | 23110001161227 |
9 | 4582086063544 |
10 | 1315334054551 |
11 | 467914868350 |
12 | 192b06868b87 |
13 | 9705cc058ba |
14 | 4793bcc935d |
15 | 24335223b51 |
hex | 1324004e297 |
1315334054551 has 16 divisors (see below), whose sum is σ = 1458007394688. Its totient is φ = 1176655572000.
The previous prime is 1315334054539. The next prime is 1315334054581. The reversal of 1315334054551 is 1554504335131.
It is a cyclic number.
It is not a de Polignac number, because 1315334054551 - 219 = 1315333530263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1315334054581) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3450561 + ... + 3812746.
It is an arithmetic number, because the mean of its divisors is an integer number (91125462168).
Almost surely, 21315334054551 is an apocalyptic number.
1315334054551 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1315334054551 is a deficient number, since it is larger than the sum of its proper divisors (142673340137).
1315334054551 is a wasteful number, since it uses less digits than its factorization.
1315334054551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7263582.
The product of its (nonzero) digits is 270000, while the sum is 40.
Adding to 1315334054551 its reverse (1554504335131), we get a palindrome (2869838389682).
The spelling of 1315334054551 in words is "one trillion, three hundred fifteen billion, three hundred thirty-four million, fifty-four thousand, five hundred fifty-one".
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