131535662117 has 2 divisors, whose sum is σ = 131535662118. Its totient is φ = 131535662116.

The previous prime is 131535662047. The next prime is 131535662119. The reversal of 131535662117 is 711266535131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105442428961 + 26093233156 = 324719^2 + 161534^2 .

It is an emirp because it is prime and its reverse (711266535131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131535662117 - 2¹⁴ = 131535645733 is a prime.

Together with 131535662119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131535662119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65767831058 + 65767831059.

It is an arithmetic number, because the mean of its divisors is an integer number (65767831059).

Almost surely, 2^131535662117 is an apocalyptic number.

It is an amenable number.

131535662117 is a deficient number, since it is larger than the sum of its proper divisors (1).

131535662117 is an equidigital number, since it uses as much as digits as its factorization.

131535662117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 113400, while the sum is 41.

The spelling of 131535662117 in words is "one hundred thirty-one billion, five hundred thirty-five million, six hundred sixty-two thousand, one hundred seventeen".