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131541267302161 is a prime number
BaseRepresentation
bin11101111010001011010110…
…100000101100011100010001
3122020202020000002100120201221
4131322023112200230130101
5114220133003412132121
61143433120213125041
736464354141465353
oct3572132640543421
9566666002316657
10131541267302161
1138a0537a133512
12129056b4329781
13585239947b082
14246a8ba4450d3
151031a5480bb41
hex77a2d682c711

131541267302161 has 2 divisors, whose sum is σ = 131541267302162. Its totient is φ = 131541267302160.

The previous prime is 131541267302129. The next prime is 131541267302183. The reversal of 131541267302161 is 161203762145131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120007643040000 + 11533624262161 = 10954800^2 + 3396119^2 .

It is a cyclic number.

It is not a de Polignac number, because 131541267302161 - 25 = 131541267302129 is a prime.

It is not a weakly prime, because it can be changed into another prime (131541267302101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65770633651080 + 65770633651081.

It is an arithmetic number, because the mean of its divisors is an integer number (65770633651081).

Almost surely, 2131541267302161 is an apocalyptic number.

It is an amenable number.

131541267302161 is a deficient number, since it is larger than the sum of its proper divisors (1).

131541267302161 is an equidigital number, since it uses as much as digits as its factorization.

131541267302161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 131541267302161 in words is "one hundred thirty-one trillion, five hundred forty-one billion, two hundred sixty-seven million, three hundred two thousand, one hundred sixty-one".