Base | Representation |
---|---|
bin | 11000100000000110… |
… | …01010010100101011 |
3 | 1020221201212212112112 |
4 | 30100003022110223 |
5 | 203414431303214 |
6 | 10013135232535 |
7 | 643654365236 |
oct | 142003122453 |
9 | 36851785475 |
10 | 13154166059 |
11 | 5640202721 |
12 | 267137874b |
13 | 13182cbc18 |
14 | 8cb01a41d |
15 | 51ec55a3e |
hex | 3100ca52b |
13154166059 has 2 divisors, whose sum is σ = 13154166060. Its totient is φ = 13154166058.
The previous prime is 13154165929. The next prime is 13154166061. The reversal of 13154166059 is 95066145131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13154166059 - 212 = 13154161963 is a prime.
Together with 13154166061, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13154169059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577083029 + 6577083030.
It is an arithmetic number, because the mean of its divisors is an integer number (6577083030).
Almost surely, 213154166059 is an apocalyptic number.
13154166059 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154166059 is an equidigital number, since it uses as much as digits as its factorization.
13154166059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 41.
The spelling of 13154166059 in words is "thirteen billion, one hundred fifty-four million, one hundred sixty-six thousand, fifty-nine".
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