13154251543247 has 2 divisors, whose sum is σ = 13154251543248. Its totient is φ = 13154251543246.

The previous prime is 13154251543201. The next prime is 13154251543249. The reversal of 13154251543247 is 74234515245131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13154251543247 is a prime.

It is a super-2 number, since 2×13154251543247² (a number of 27 digits) contains 22 as substring.

Together with 13154251543249, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13154251543249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577125771623 + 6577125771624.

It is an arithmetic number, because the mean of its divisors is an integer number (6577125771624).

Almost surely, 2^{13154251543247} is an apocalyptic number.

13154251543247 is a deficient number, since it is larger than the sum of its proper divisors (1).

13154251543247 is an equidigital number, since it uses as much as digits as its factorization.

13154251543247 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2016000, while the sum is 47.

Adding to 13154251543247 its reverse (74234515245131), we get a palindrome (87388766788378).

The spelling of 13154251543247 in words is "thirteen trillion, one hundred fifty-four billion, two hundred fifty-one million, five hundred forty-three thousand, two hundred forty-seven".