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13154433133 is a prime number
BaseRepresentation
bin11000100000001000…
…01011100001101101
31020221202101102220011
430100010023201231
5203420013330013
610013145053221
7643656560002
oct142004134155
936852342804
1013154433133
115640375346
122671487211
13131839365a
148cb0898a9
1551eca9c3d
hex31010b86d

13154433133 has 2 divisors, whose sum is σ = 13154433134. Its totient is φ = 13154433132.

The previous prime is 13154433119. The next prime is 13154433151. The reversal of 13154433133 is 33133445131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6789265609 + 6365167524 = 82397^2 + 79782^2 .

It is a cyclic number.

It is not a de Polignac number, because 13154433133 - 221 = 13152335981 is a prime.

It is a super-2 number, since 2×131544331332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13154433095 and 13154433104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13154433113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577216566 + 6577216567.

It is an arithmetic number, because the mean of its divisors is an integer number (6577216567).

Almost surely, 213154433133 is an apocalyptic number.

It is an amenable number.

13154433133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13154433133 is an equidigital number, since it uses as much as digits as its factorization.

13154433133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19440, while the sum is 31.

Adding to 13154433133 its reverse (33133445131), we get a palindrome (46287878264).

The spelling of 13154433133 in words is "thirteen billion, one hundred fifty-four million, four hundred thirty-three thousand, one hundred thirty-three".