Base | Representation |
---|---|
bin | 111101010000011111… |
… | …1100011010111000000 |
3 | 110120112221121002122012 |
4 | 1322200333203113000 |
5 | 4123403302031334 |
6 | 140233325432052 |
7 | 12334634556002 |
oct | 1724077432700 |
9 | 416487532565 |
10 | 131550033344 |
11 | 50876623124 |
12 | 215b3a0b628 |
13 | c536064422 |
14 | 651d2b4372 |
15 | 364de929ce |
hex | 1ea0fe35c0 |
131550033344 has 14 divisors (see below), whose sum is σ = 261044597544. Its totient is φ = 65775016640.
The previous prime is 131550033337. The next prime is 131550033361. The reversal of 131550033344 is 443330055131.
It is a super-2 number, since 2×1315500333442 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is a self number, because there is not a number n which added to its sum of digits gives 131550033344.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1027734572 + ... + 1027734699.
Almost surely, 2131550033344 is an apocalyptic number.
It is an amenable number.
131550033344 is a deficient number, since it is larger than the sum of its proper divisors (129494564200).
131550033344 is an equidigital number, since it uses as much as digits as its factorization.
131550033344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2055469283 (or 2055469273 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 131550033344 its reverse (443330055131), we get a palindrome (574880088475).
The spelling of 131550033344 in words is "one hundred thirty-one billion, five hundred fifty million, thirty-three thousand, three hundred forty-four".
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