Base | Representation |
---|---|
bin | 1011111101101110111110… |
… | …1011111110010001010110 |
3 | 1201120121220021122111101211 |
4 | 2333123233223332101112 |
5 | 3211013333023022410 |
6 | 43551230502012034 |
7 | 2525301252502213 |
oct | 277335753762126 |
9 | 51517807574354 |
10 | 13155211142230 |
11 | 4212103809163 |
12 | 158569971701a |
13 | 7456b9a52191 |
14 | 336a0391ab0a |
15 | 17c2e59c868a |
hex | bf6efafe456 |
13155211142230 has 8 divisors (see below), whose sum is σ = 23679380056032. Its totient is φ = 5262084456888.
The previous prime is 13155211142207. The next prime is 13155211142287. The reversal of 13155211142230 is 3224111255131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13155211142192 and 13155211142201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 657760557102 + ... + 657760557121.
It is an arithmetic number, because the mean of its divisors is an integer number (2959922507004).
Almost surely, 213155211142230 is an apocalyptic number.
13155211142230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13155211142230 is a deficient number, since it is larger than the sum of its proper divisors (10524168913802).
13155211142230 is a wasteful number, since it uses less digits than its factorization.
13155211142230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1315521114230.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 13155211142230 its reverse (3224111255131), we get a palindrome (16379322397361).
The spelling of 13155211142230 in words is "thirteen trillion, one hundred fifty-five billion, two hundred eleven million, one hundred forty-two thousand, two hundred thirty".
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