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1315651129693 is a prime number
BaseRepresentation
bin10011001001010010111…
…010110001000101011101
311122202220222201012221021
4103021102322301011131
5133023423142122233
62444222441404141
7164024030041165
oct23112272610535
94582828635837
101315651129693
11467a6784461a
12192b94a99651
13970b0801724
144796c0655a5
1524352ea6e2d
hex13252eb115d

1315651129693 has 2 divisors, whose sum is σ = 1315651129694. Its totient is φ = 1315651129692.

The previous prime is 1315651129631. The next prime is 1315651129733. The reversal of 1315651129693 is 3969211565131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1181227706649 + 134423423044 = 1086843^2 + 366638^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1315651129693 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1315651129693.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1315651129603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657825564846 + 657825564847.

It is an arithmetic number, because the mean of its divisors is an integer number (657825564847).

Almost surely, 21315651129693 is an apocalyptic number.

It is an amenable number.

1315651129693 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315651129693 is an equidigital number, since it uses as much as digits as its factorization.

1315651129693 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1312200, while the sum is 52.

The spelling of 1315651129693 in words is "one trillion, three hundred fifteen billion, six hundred fifty-one million, one hundred twenty-nine thousand, six hundred ninety-three".