Base | Representation |
---|---|
bin | 10011001001010010111… |
… | …010110001000101011101 |
3 | 11122202220222201012221021 |
4 | 103021102322301011131 |
5 | 133023423142122233 |
6 | 2444222441404141 |
7 | 164024030041165 |
oct | 23112272610535 |
9 | 4582828635837 |
10 | 1315651129693 |
11 | 467a6784461a |
12 | 192b94a99651 |
13 | 970b0801724 |
14 | 4796c0655a5 |
15 | 24352ea6e2d |
hex | 13252eb115d |
1315651129693 has 2 divisors, whose sum is σ = 1315651129694. Its totient is φ = 1315651129692.
The previous prime is 1315651129631. The next prime is 1315651129733. The reversal of 1315651129693 is 3969211565131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1181227706649 + 134423423044 = 1086843^2 + 366638^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1315651129693 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1315651129693.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1315651129603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657825564846 + 657825564847.
It is an arithmetic number, because the mean of its divisors is an integer number (657825564847).
Almost surely, 21315651129693 is an apocalyptic number.
It is an amenable number.
1315651129693 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315651129693 is an equidigital number, since it uses as much as digits as its factorization.
1315651129693 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1312200, while the sum is 52.
The spelling of 1315651129693 in words is "one trillion, three hundred fifteen billion, six hundred fifty-one million, one hundred twenty-nine thousand, six hundred ninety-three".
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