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131566060341481 is a prime number
BaseRepresentation
bin11101111010100010011100…
…010010101000100011101001
3122020211120222221211110212111
4131322202130102220203221
5114221034242421411411
61143452340322042321
736466222424032003
oct3572423422504351
9566746887743774
10131566060341481
1138a14942162957
121290a4734a93a1
13585481ab60c3c
14246bb8d117373
15103250624c721
hex77a89c4a88e9

131566060341481 has 2 divisors, whose sum is σ = 131566060341482. Its totient is φ = 131566060341480.

The previous prime is 131566060341449. The next prime is 131566060341517. The reversal of 131566060341481 is 184143060665131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127746302805081 + 3819757536400 = 11302491^2 + 1954420^2 .

It is a cyclic number.

It is not a de Polignac number, because 131566060341481 - 25 = 131566060341449 is a prime.

It is a super-2 number, since 2×1315660603414812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131566060371481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65783030170740 + 65783030170741.

It is an arithmetic number, because the mean of its divisors is an integer number (65783030170741).

Almost surely, 2131566060341481 is an apocalyptic number.

It is an amenable number.

131566060341481 is a deficient number, since it is larger than the sum of its proper divisors (1).

131566060341481 is an equidigital number, since it uses as much as digits as its factorization.

131566060341481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1244160, while the sum is 49.

The spelling of 131566060341481 in words is "one hundred thirty-one trillion, five hundred sixty-six billion, sixty million, three hundred forty-one thousand, four hundred eighty-one".