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131566060341517 is a prime number
BaseRepresentation
bin11101111010100010011100…
…010010101000100100001101
3122020211120222221211110220211
4131322202130102220210031
5114221034242421412032
61143452340322042421
736466222424032054
oct3572423422504415
9566746887743824
10131566060341517
1138a1494216298a
121290a4734a9411
13585481ab60c69
14246bb8d11739b
15103250624c747
hex77a89c4a890d

131566060341517 has 2 divisors, whose sum is σ = 131566060341518. Its totient is φ = 131566060341516.

The previous prime is 131566060341481. The next prime is 131566060341587. The reversal of 131566060341517 is 715143060665131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126822598494916 + 4743461846601 = 11261554^2 + 2177949^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131566060341517 is a prime.

It is a super-2 number, since 2×1315660603415172 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131566060341587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65783030170758 + 65783030170759.

It is an arithmetic number, because the mean of its divisors is an integer number (65783030170759).

Almost surely, 2131566060341517 is an apocalyptic number.

It is an amenable number.

131566060341517 is a deficient number, since it is larger than the sum of its proper divisors (1).

131566060341517 is an equidigital number, since it uses as much as digits as its factorization.

131566060341517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 49.

The spelling of 131566060341517 in words is "one hundred thirty-one trillion, five hundred sixty-six billion, sixty million, three hundred forty-one thousand, five hundred seventeen".