Base | Representation |
---|---|
bin | 11000100000011000… |
… | …11111110101011111 |
3 | 1020221220111012202102 |
4 | 30100030133311133 |
5 | 203421043112341 |
6 | 10013303515315 |
7 | 644014240451 |
oct | 142014376537 |
9 | 36856435672 |
10 | 13156613471 |
11 | 5641624481 |
12 | 2672158b3b |
13 | 1318977bb1 |
14 | 8cb4962d1 |
15 | 52008ac9b |
hex | 31031fd5f |
13156613471 has 2 divisors, whose sum is σ = 13156613472. Its totient is φ = 13156613470.
The previous prime is 13156613467. The next prime is 13156613473. The reversal of 13156613471 is 17431665131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13156613471 - 22 = 13156613467 is a prime.
It is a super-3 number, since 3×131566134713 (a number of 31 digits) contains 333 as substring.
Together with 13156613473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13156613473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6578306735 + 6578306736.
It is an arithmetic number, because the mean of its divisors is an integer number (6578306736).
Almost surely, 213156613471 is an apocalyptic number.
13156613471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13156613471 is an equidigital number, since it uses as much as digits as its factorization.
13156613471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 45360, while the sum is 38.
The spelling of 13156613471 in words is "thirteen billion, one hundred fifty-six million, six hundred thirteen thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •