1316000442853 has 4 divisors (see below), whose sum is σ = 1316102479200. Its totient is φ = 1315898406508.

The previous prime is 1316000442851. The next prime is 1316000442877. The reversal of 1316000442853 is 3582440006131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1316000442853 - 2¹ = 1316000442851 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1316000442851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50998825 + ... + 51024622.

It is an arithmetic number, because the mean of its divisors is an integer number (329025619800).

Almost surely, 2^{1316000442853} is an apocalyptic number.

It is an amenable number.

1316000442853 is a deficient number, since it is larger than the sum of its proper divisors (102036347).

1316000442853 is a wasteful number, since it uses less digits than its factorization.

1316000442853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102036346.

The product of its (nonzero) digits is 69120, while the sum is 37.

Adding to 1316000442853 its reverse (3582440006131), we get a palindrome (4898440448984).

The spelling of 1316000442853 in words is "one trillion, three hundred sixteen billion, four hundred forty-two thousand, eight hundred fifty-three".