Base | Representation |
---|---|
bin | 10011001001101111100… |
… | …110000001011110001101 |
3 | 11122211011111222200221011 |
4 | 103021233212001132031 |
5 | 133030414322343203 |
6 | 2444342305205221 |
7 | 164041661244103 |
oct | 23115746013615 |
9 | 4584144880834 |
10 | 1316132231053 |
11 | 468194373152 |
12 | 1930aa030811 |
13 | 9715939a7a3 |
14 | 479b5cdbc73 |
15 | 2438033a76d |
hex | 1326f98178d |
1316132231053 has 2 divisors, whose sum is σ = 1316132231054. Its totient is φ = 1316132231052.
The previous prime is 1316132231041. The next prime is 1316132231059. The reversal of 1316132231053 is 3501322316131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1212645844804 + 103486386249 = 1101202^2 + 321693^2 .
It is a cyclic number.
It is not a de Polignac number, because 1316132231053 - 25 = 1316132231021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316132231059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658066115526 + 658066115527.
It is an arithmetic number, because the mean of its divisors is an integer number (658066115527).
Almost surely, 21316132231053 is an apocalyptic number.
It is an amenable number.
1316132231053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316132231053 is an equidigital number, since it uses as much as digits as its factorization.
1316132231053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 1316132231053 its reverse (3501322316131), we get a palindrome (4817454547184).
The spelling of 1316132231053 in words is "one trillion, three hundred sixteen billion, one hundred thirty-two million, two hundred thirty-one thousand, fifty-three".
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