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13161434050437 = 34387144683479
BaseRepresentation
bin1011111110000110001010…
…0110011110111110000101
31201121012221222010222122120
42333201202212132332011
53211114104104103222
643554140200320153
72525611414365561
oct277414246367605
951535858128576
1013161434050437
114214807449202
121586935773059
1374616c06629a
143370341926a1
1517c55be9315c
hexbf86299ef85

13161434050437 has 4 divisors (see below), whose sum is σ = 17548578733920. Its totient is φ = 8774289366956.

The previous prime is 13161434050409. The next prime is 13161434050447. The reversal of 13161434050437 is 73405043416131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13161434050437 - 27 = 13161434050309 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13161434050447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2193572341737 + ... + 2193572341742.

It is an arithmetic number, because the mean of its divisors is an integer number (4387144683480).

Almost surely, 213161434050437 is an apocalyptic number.

It is an amenable number.

13161434050437 is a deficient number, since it is larger than the sum of its proper divisors (4387144683483).

13161434050437 is an equidigital number, since it uses as much as digits as its factorization.

13161434050437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4387144683482.

The product of its (nonzero) digits is 362880, while the sum is 42.

Adding to 13161434050437 its reverse (73405043416131), we get a palindrome (86566477466568).

The spelling of 13161434050437 in words is "thirteen trillion, one hundred sixty-one billion, four hundred thirty-four million, fifty thousand, four hundred thirty-seven".

Divisors: 1 3 4387144683479 13161434050437