Base | Representation |
---|---|
bin | 1011111110000110010000… |
… | …1001111110001011001101 |
3 | 1201121020000210012222210011 |
4 | 2333201210021332023031 |
5 | 3211114132243134014 |
6 | 43554142531313221 |
7 | 2525612152150015 |
oct | 277414411761315 |
9 | 51536023188704 |
10 | 13161460130509 |
11 | 4214820141589 |
12 | 158694244b811 |
13 | 746174597c92 |
14 | 337037820c45 |
15 | 17c55e3e57c4 |
hex | bf86427e2cd |
13161460130509 has 2 divisors, whose sum is σ = 13161460130510. Its totient is φ = 13161460130508.
The previous prime is 13161460130501. The next prime is 13161460130551. The reversal of 13161460130509 is 90503106416131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9952983877225 + 3208476253284 = 3154835^2 + 1791222^2 .
It is a cyclic number.
It is not a de Polignac number, because 13161460130509 - 23 = 13161460130501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13161460130501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580730065254 + 6580730065255.
It is an arithmetic number, because the mean of its divisors is an integer number (6580730065255).
Almost surely, 213161460130509 is an apocalyptic number.
It is an amenable number.
13161460130509 is a deficient number, since it is larger than the sum of its proper divisors (1).
13161460130509 is an equidigital number, since it uses as much as digits as its factorization.
13161460130509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 40.
The spelling of 13161460130509 in words is "thirteen trillion, one hundred sixty-one billion, four hundred sixty million, one hundred thirty thousand, five hundred nine".
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