Base | Representation |
---|---|
bin | 1011111110000110010000… |
… | …1001111110001011110111 |
3 | 1201121020000210012222211201 |
4 | 2333201210021332023313 |
5 | 3211114132243134201 |
6 | 43554142531313331 |
7 | 2525612152150105 |
oct | 277414411761367 |
9 | 51536023188751 |
10 | 13161460130551 |
11 | 4214820141617 |
12 | 158694244b847 |
13 | 746174597cc5 |
14 | 337037820c75 |
15 | 17c55e3e5801 |
hex | bf86427e2f7 |
13161460130551 has 2 divisors, whose sum is σ = 13161460130552. Its totient is φ = 13161460130550.
The previous prime is 13161460130509. The next prime is 13161460130597. The reversal of 13161460130551 is 15503106416131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13161460130551 - 223 = 13161451741943 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13161460130551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13161460130501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580730065275 + 6580730065276.
It is an arithmetic number, because the mean of its divisors is an integer number (6580730065276).
Almost surely, 213161460130551 is an apocalyptic number.
13161460130551 is a deficient number, since it is larger than the sum of its proper divisors (1).
13161460130551 is an equidigital number, since it uses as much as digits as its factorization.
13161460130551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 37.
Adding to 13161460130551 its reverse (15503106416131), we get a palindrome (28664566546682).
The spelling of 13161460130551 in words is "thirteen trillion, one hundred sixty-one billion, four hundred sixty million, one hundred thirty thousand, five hundred fifty-one".
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