Base | Representation |
---|---|
bin | 1011111110001001100010… |
… | …1010001110011000010111 |
3 | 1201121022022011201211120001 |
4 | 2333202120222032120113 |
5 | 3211122433244010402 |
6 | 43554410155352131 |
7 | 2525643036342532 |
oct | 277423052163027 |
9 | 51538264654501 |
10 | 13162341000727 |
11 | 42151323983a6 |
12 | 1586b49452647 |
13 | 746284c24369 |
14 | 3370bc7dba19 |
15 | 17c5b18e4187 |
hex | bf898a8e617 |
13162341000727 has 2 divisors, whose sum is σ = 13162341000728. Its totient is φ = 13162341000726.
The previous prime is 13162341000713. The next prime is 13162341000761. The reversal of 13162341000727 is 72700014326131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13162341000727 is a prime.
It is a super-3 number, since 3×131623410007273 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13162341000427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6581170500363 + 6581170500364.
It is an arithmetic number, because the mean of its divisors is an integer number (6581170500364).
Almost surely, 213162341000727 is an apocalyptic number.
13162341000727 is a deficient number, since it is larger than the sum of its proper divisors (1).
13162341000727 is an equidigital number, since it uses as much as digits as its factorization.
13162341000727 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42336, while the sum is 37.
Adding to 13162341000727 its reverse (72700014326131), we get a palindrome (85862355326858).
The spelling of 13162341000727 in words is "thirteen trillion, one hundred sixty-two billion, three hundred forty-one million, seven hundred twenty-seven", and thus it is an aban number.
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