Base | Representation |
---|---|
bin | 1011111110001001100010… |
… | …1010001110100111100111 |
3 | 1201121022022011201212220012 |
4 | 2333202120222032213213 |
5 | 3211122433244023303 |
6 | 43554410155400435 |
7 | 2525643036345425 |
oct | 277423052164747 |
9 | 51538264655805 |
10 | 13162341001703 |
11 | 4215132399103 |
12 | 1586b4945311b |
13 | 746284c2493a |
14 | 3370bc7dc115 |
15 | 17c5b18e45d8 |
hex | bf898a8e9e7 |
13162341001703 has 2 divisors, whose sum is σ = 13162341001704. Its totient is φ = 13162341001702.
The previous prime is 13162341001673. The next prime is 13162341001751. The reversal of 13162341001703 is 30710014326131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13162341001703 - 26 = 13162341001639 is a prime.
It is a super-2 number, since 2×131623410017032 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13162341001703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13162341031703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6581170500851 + 6581170500852.
It is an arithmetic number, because the mean of its divisors is an integer number (6581170500852).
Almost surely, 213162341001703 is an apocalyptic number.
13162341001703 is a deficient number, since it is larger than the sum of its proper divisors (1).
13162341001703 is an equidigital number, since it uses as much as digits as its factorization.
13162341001703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 32.
Adding to 13162341001703 its reverse (30710014326131), we get a palindrome (43872355327834).
The spelling of 13162341001703 in words is "thirteen trillion, one hundred sixty-two billion, three hundred forty-one million, one thousand, seven hundred three".
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