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13162341001703 is a prime number
BaseRepresentation
bin1011111110001001100010…
…1010001110100111100111
31201121022022011201212220012
42333202120222032213213
53211122433244023303
643554410155400435
72525643036345425
oct277423052164747
951538264655805
1013162341001703
114215132399103
121586b4945311b
13746284c2493a
143370bc7dc115
1517c5b18e45d8
hexbf898a8e9e7

13162341001703 has 2 divisors, whose sum is σ = 13162341001704. Its totient is φ = 13162341001702.

The previous prime is 13162341001673. The next prime is 13162341001751. The reversal of 13162341001703 is 30710014326131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13162341001703 - 26 = 13162341001639 is a prime.

It is a super-2 number, since 2×131623410017032 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13162341001703.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13162341031703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6581170500851 + 6581170500852.

It is an arithmetic number, because the mean of its divisors is an integer number (6581170500852).

Almost surely, 213162341001703 is an apocalyptic number.

13162341001703 is a deficient number, since it is larger than the sum of its proper divisors (1).

13162341001703 is an equidigital number, since it uses as much as digits as its factorization.

13162341001703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 32.

Adding to 13162341001703 its reverse (30710014326131), we get a palindrome (43872355327834).

The spelling of 13162341001703 in words is "thirteen trillion, one hundred sixty-two billion, three hundred forty-one million, one thousand, seven hundred three".