13162341001751 has 2 divisors, whose sum is σ = 13162341001752. Its totient is φ = 13162341001750.

The previous prime is 13162341001703. The next prime is 13162341001781. The reversal of 13162341001751 is 15710014326131.

It is a strong prime.

It is an emirp because it is prime and its reverse (15710014326131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13162341001751 - 2¹⁰ = 13162341000727 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13162341001781) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6581170500875 + 6581170500876.

It is an arithmetic number, because the mean of its divisors is an integer number (6581170500876).

Almost surely, 2^{13162341001751} is an apocalyptic number.

13162341001751 is a deficient number, since it is larger than the sum of its proper divisors (1).

13162341001751 is an equidigital number, since it uses as much as digits as its factorization.

13162341001751 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 35.

Adding to 13162341001751 its reverse (15710014326131), we get a palindrome (28872355327882).

The spelling of 13162341001751 in words is "thirteen trillion, one hundred sixty-two billion, three hundred forty-one million, one thousand, seven hundred fifty-one".