Base | Representation |
---|---|
bin | 1011111110010011100010… |
… | …0001010101010100111101 |
3 | 1201121120020002102202102211 |
4 | 2333210320201111110331 |
5 | 3211143431343240240 |
6 | 43555532244420421 |
7 | 2526066354225625 |
oct | 277447041252475 |
9 | 51546202382384 |
10 | 13165023024445 |
11 | 4216289316526 |
12 | 15875776a7711 |
13 | 7465c1785846 |
14 | 337294ab1885 |
15 | 17c6bc0c7bea |
hex | bf93885553d |
13165023024445 has 16 divisors (see below), whose sum is σ = 17607708815040. Its totient is φ = 9390778032384.
The previous prime is 13165023024437. The next prime is 13165023024551. The reversal of 13165023024445 is 54442032056131.
It is a cyclic number.
It is not a de Polignac number, because 13165023024445 - 23 = 13165023024437 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13165023024398 and 13165023024407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4075856907 + ... + 4075860136.
It is an arithmetic number, because the mean of its divisors is an integer number (1100481800940).
Almost surely, 213165023024445 is an apocalyptic number.
It is an amenable number.
13165023024445 is a deficient number, since it is larger than the sum of its proper divisors (4442685790595).
13165023024445 is a wasteful number, since it uses less digits than its factorization.
13165023024445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8151717084.
The product of its (nonzero) digits is 345600, while the sum is 40.
The spelling of 13165023024445 in words is "thirteen trillion, one hundred sixty-five billion, twenty-three million, twenty-four thousand, four hundred forty-five".
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