Base | Representation |
---|---|
bin | 11000100001111010… |
… | …10111110000111111 |
3 | 1020222210121010111221 |
4 | 30100331113300333 |
5 | 203432333103341 |
6 | 10014442254211 |
7 | 644231161306 |
oct | 142075276077 |
9 | 36883533457 |
10 | 13169425471 |
11 | 5648885304 |
12 | 26764b7367 |
13 | 131b512667 |
14 | 8cd06d43d |
15 | 52126bed1 |
hex | 310f57c3f |
13169425471 has 2 divisors, whose sum is σ = 13169425472. Its totient is φ = 13169425470.
The previous prime is 13169425457. The next prime is 13169425499. The reversal of 13169425471 is 17452496131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13169425471 - 25 = 13169425439 is a prime.
It is a super-3 number, since 3×131694254713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13169405471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6584712735 + 6584712736.
It is an arithmetic number, because the mean of its divisors is an integer number (6584712736).
Almost surely, 213169425471 is an apocalyptic number.
13169425471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13169425471 is an equidigital number, since it uses as much as digits as its factorization.
13169425471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 181440, while the sum is 43.
The spelling of 13169425471 in words is "thirteen billion, one hundred sixty-nine million, four hundred twenty-five thousand, four hundred seventy-one".
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