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131712599040 = 21035112926881
BaseRepresentation
bin111101010101010101…
…1101100010000000000
3110120222021111021211220
41322222223230100000
54124221411132130
6140301414035040
712341650422321
oct1725253542000
9416867437756
10131712599040
115094a368140
122163a348a80
13c560942949
146536b10448
15365d3a5410
hex1eaaaec400

131712599040 has 352 divisors, whose sum is σ = 475437202560. Its totient is φ = 30828134400.

The previous prime is 131712599023. The next prime is 131712599077. The reversal of 131712599040 is 40995217131.

It is a tau number, because it is divible by the number of its divisors (352).

It is a junction number, because it is equal to n+sod(n) for n = 131712598983 and 131712599001.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4886400 + ... + 4913280.

Almost surely, 2131712599040 is an apocalyptic number.

131712599040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131712599040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (237718601280).

131712599040 is an abundant number, since it is smaller than the sum of its proper divisors (343724603520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131712599040 is a wasteful number, since it uses less digits than its factorization.

131712599040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26949 (or 26931 counting only the distinct ones).

The product of its (nonzero) digits is 68040, while the sum is 42.

The spelling of 131712599040 in words is "one hundred thirty-one billion, seven hundred twelve million, five hundred ninety-nine thousand, forty".