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131720246689 is a prime number
BaseRepresentation
bin111101010101100100…
…0110111010110100001
3110120222210212211110011
41322223020313112201
54124230340343224
6140302250004521
712342102423553
oct1725310672641
9416883784404
10131720246689
1150953710a09
1221640a16741
13c5623bc895
146537b414d3
15365ddb6394
hex1eab2375a1

131720246689 has 2 divisors, whose sum is σ = 131720246690. Its totient is φ = 131720246688.

The previous prime is 131720246687. The next prime is 131720246747. The reversal of 131720246689 is 986642027131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115611560289 + 16108686400 = 340017^2 + 126920^2 .

It is a cyclic number.

It is not a de Polignac number, because 131720246689 - 21 = 131720246687 is a prime.

It is a super-2 number, since 2×1317202466892 (a number of 23 digits) contains 22 as substring.

Together with 131720246687, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131720246687) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65860123344 + 65860123345.

It is an arithmetic number, because the mean of its divisors is an integer number (65860123345).

Almost surely, 2131720246689 is an apocalyptic number.

It is an amenable number.

131720246689 is a deficient number, since it is larger than the sum of its proper divisors (1).

131720246689 is an equidigital number, since it uses as much as digits as its factorization.

131720246689 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 870912, while the sum is 49.

The spelling of 131720246689 in words is "one hundred thirty-one billion, seven hundred twenty million, two hundred forty-six thousand, six hundred eighty-nine".