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1318320704750 = 2537171971107307
BaseRepresentation
bin10011001011110010000…
…010011000110011101110
311200000211000222200110112
4103023302002120303232
5133044410100023000
62445343403540022
7164150134045640
oct23136202306356
94600730880415
101318320704750
1146910773a8a5
121935bab2a612
13974178c493a
1447b42818890
152445c52c235
hex132f2098cee

1318320704750 has 512 divisors, whose sum is σ = 3228087582720. Its totient is φ = 392345856000.

The previous prime is 1318320704663. The next prime is 1318320704761. The reversal of 1318320704750 is 574070238131.

It is a junction number, because it is equal to n+sod(n) for n = 1318320704698 and 1318320704707.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 4294204097 + ... + 4294204403.

It is an arithmetic number, because the mean of its divisors is an integer number (6304858560).

Almost surely, 21318320704750 is an apocalyptic number.

1318320704750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1318320704750 is an abundant number, since it is smaller than the sum of its proper divisors (1909766877970).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1318320704750 is a wasteful number, since it uses less digits than its factorization.

1318320704750 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 545 (or 535 counting only the distinct ones).

The product of its (nonzero) digits is 141120, while the sum is 41.

The spelling of 1318320704750 in words is "one trillion, three hundred eighteen billion, three hundred twenty million, seven hundred four thousand, seven hundred fifty".