13194139533313 has 4 divisors (see below), whose sum is σ = 13322237975488. Its totient is φ = 13066041091140.

The previous prime is 13194139533299. The next prime is 13194139533349. The reversal of 13194139533313 is 31333593149131.

13194139533313 = 2097151² + 2097152² + 2097153².

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13194139533313 - 2³³ = 13185549598721 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13194139533383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (3) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64049220933 + ... + 64049221138.

It is an arithmetic number, because the mean of its divisors is an integer number (3330559493872).

It is a Proth number, since it is equal to 3 ⋅ 2⁴² + 1 and 3 < 2⁴².

Almost surely, 2^{13194139533313} is an apocalyptic number.

It is an amenable number.

13194139533313 is a deficient number, since it is larger than the sum of its proper divisors (128098442175).

13194139533313 is a wasteful number, since it uses less digits than its factorization.

13194139533313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128098442174.

The product of its digits is 1180980, while the sum is 49.

The spelling of 13194139533313 in words is "thirteen trillion, one hundred ninety-four billion, one hundred thirty-nine million, five hundred thirty-three thousand, three hundred thirteen".